1773. 统计匹配检索规则的物品数量

给你一个数组 items ，其中 items[i] = [typei, colori, namei] ，描述第 i 件物品的类型、颜色以及名称。

另给你一条由两个字符串 ruleKey 和 ruleValue 表示的检索规则。

如果第 i 件物品能满足下述条件之一，则认为该物品与给定的检索规则 匹配 ：

• ruleKey == "type" 且 ruleValue == typei 。

• ruleKey == "color" 且 ruleValue == colori 。

• ruleKey == "name" 且 ruleValue == namei 。

统计并返回 匹配检索规则的物品数量 。

示例 1：

输入：items = [["phone","blue","pixel"],["computer","silver","lenovo"],["phone","gold","iphone"]], ruleKey = "color", ruleValue = "silver"
输出：1
解释：只有一件物品匹配检索规则，这件物品是 ["computer","silver","lenovo"] 。

示例 2：

输入：items = [["phone","blue","pixel"],["computer","silver","phone"],["phone","gold","iphone"]], ruleKey = "type", ruleValue = "phone"
输出：2
解释：只有两件物品匹配检索规则，这两件物品分别是 ["phone","blue","pixel"] 和 ["phone","gold","iphone"] 。注意，["computer","silver","phone"] 未匹配检索规则。

提示：

• 1 <= items.length <= 104

• 1 <= typei.length, colori.length, namei.length, ruleValue.length <= 10

• ruleKey 等于 "type"、"color" 或 "name"

• 所有字符串仅由小写字母组成

解答

找到匹配键的索引再对比

class Solution {
    public int countMatches(List<List<String>> items, String ruleKey, String ruleValue) {
        int result = 0;
        int index = 0;
        if("color".equals(ruleKey)){
            index = 1;
        }else if("name".equals(ruleKey)){
            index = 2;
        }
        for(List<String> item : items){
            if(ruleValue.equals(item.get(index))){
                result++;
            }
        }
        return result;
    }
}